Sag from a known tension

Code-Snippets

curl "https://api.oanor.com/slackline-api/v1/sag" \
  -H "x-oanor-key: oanor_test_..."

await fetch("https://api.oanor.com/slackline-api/v1/sag", {
  headers: { "x-oanor-key": "oanor_test_..." }
});

$ch = curl_init("https://api.oanor.com/slackline-api/v1/sag");
curl_setopt($ch, CURLOPT_HTTPHEADER, ["x-oanor-key: oanor_test_..."]);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
$out = curl_exec($ch);

import requests
requests.get(
    "https://api.oanor.com/slackline-api/v1/sag",
    headers={"x-oanor-key": "oanor_test_..."}
)

Beispiel-Response

Echte Antwort dieses Endpoints, erfasst beim letzten Health-Check.

{
    "data": {
        "note": "The sag a mid-span load settles to for a given line tension: sin(angle) = body weight ÷ twice the tension, and the sag = half the span × tan(angle). Tighten the line (raise the tension) and the sag — and the angle — shrink, but the anchor load climbs; slacken it and the line dips deeper but pulls the anchors far less. If the tension is below half the body weight the line cannot hold the load at the centre at all.",
        "sag_m": 1.5,
        "inputs": {
            "load_kg": 80,
            "tension_n": 3292,
            "line_length_m": 25
        },
        "load_force_n": 784.53,
        "sag_angle_deg": 6.843
    },
    "meta": {
        "timestamp": "2026-06-07T08:17:55.871Z",
        "request_id": "1a63b174-97f9-4897-b16e-d7dcedd41f56"
    },
    "status": "ok",
    "message": "Sag",
    "success": true
}